Question

Calculate the mass of the sodium acetate (CH3COOHNa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol-1.

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Answer 1

Explanation:

0.375 M solution of CH

3

COONa = 0.375 moles of CH

3

COONa/1000ml

No. of moles of CH

3

COONa in 500ml =

1000

0.375

×500=0.1875 moles

Molar mass of sodium acetate = 82.0245 g/mole

∴ mass of CH

3

COONa required =82.0245×0.1875=15.38g