Question

Calculate the mass of the solute C6H6 and the mass of the solvent tetrahydrofuran that should be added to prepare 1.63 kg of a solution that is 1.42 m. Please give full explanation.

Answer 1

Answer:

Calculate the mass of the solute C6H6 and the mass of the solvent tetrahydrofuran that should be added to prepare 1.63 kg of a solution that is 1.42 m.

Solution:

1.42 m means 1.42 mole of C6H6in 1 kg of tetrahydrofuran

1.42 mol times 78.1134 g/mol = 110.921 g

110.921 g + 1000 g = 1110.921 g

110.921 is to 1110.921 as x is to 1630

x = 162.75 g

To check, do this:

162.75 g / 78.1134 g/mol = 2.08351 mol

1630 g - 162.75 g = 1467.25 g

2.08351 mol / 1.46725 kg = 1.42 m

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