calculate the mass of the solute in 100cm^3 of N/10 KOH
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Answer:
100cmcube= 0.1litre
Molarity × valency factor =normality
M × 1 = 0.1N
So molarity =0.1M
It means 0.1 mole in1L solution,we have 0.1L solution so no. of moles equal to 0.01 mole
Mole of KOH =56g
0.001mole KOH= 0.56g
Explanation:
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