Question

Calculate the mass of titanium (IV) chloride produced by the reaction of 3.25 grams of Ti metal and excess chlorine based on the reaction. (Atomic mass: Ti = 57.9 amu, Cl = 35.5 amu.) ​

Answer 1

TiCl

4

Explanation:

The idea here is that the difference between the mass of the titanium chloride and the mass of titanium metal will represent the mass of chlorine.

This means that you can find how much chlorine was needed to form that much titanium chloride by

m

titanium chloride

=

m

chlorine

+

m

titanium

n

chlorine

=

10.31 g

−

2.60 g

=

7.71 g Cl

So, your titanium chloride contains

2.60 g

of titanium and

7.71 g

of chlorine. To get the compound's empirical formula you need to first establish how many moles of each element you get in that sample.

To do that, use the two elements' respective molar masses

For Ti:

2.60

g

47.867

g

mol

=

0.054317 moles Ti

and

For Cl:

7.71

g

35.453

g

mol

=

0.21747 moles Cl

To find the mole ratio that exists between the two elements in the sample, divide both numbers of moles by the smallest of the two

For Ti:

0.054317

moles

0.054317

moles

=

1

For Cl:

0.21747

moles

0.054317

moles

=

4.0037

≈

4

This means that the empirical formula will be

Ti

1

Cl

4

, or

TiCl

4

Hope this helps! ;D

Answer 2

The idea here is that the difference between the mass of the titanium chloride and the mass of titanium metal will represent the mass of chlorine.

This means that you can find how much chlorine was needed to form that much titanium chloride by

m(titanium chloride)=$\frac{m(chlorine)+m(titanium)}{n(chlorine)}$

                                = 10.31 g−2.60 g= 7.71 g Cl

So, your titanium chloride contains 2.60 g of titanium and 7.71 g of chlorine. To get the compound's empirical formula you need to first establish how many moles of each element you get in that sample.

To do that, use the two elements' respective molar masses

For Ti:

2.60g/47.867gmol=0.054317 moles Ti

and

For Cl

7.71g/35.453 gmol=0.21747 moles Cl

To find the mole ratio that exists between the two elements in the sample, divide both numbers of moles by the smallest of the two

For Ti

0.054317moles/ 0.054317 moles =1

For Cl

0.21747 moles /0.054317 moles=4.0037 ≈ 4

This means that the empirical formula will be Ti1Cl 4 , or

TiCl4.

For,

Molar Mass Of titanium chloride= 57.9+35.5=93.4