Calculate the mass of unreacted oxygen gas. If 100g of oxygen gas is passed to burn 10g of hydrogen gas to water. Also determine the amount of water produced
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If this is a numerical problem, then the answer is that 10g or 5 moles of Hydrogen react with 2.5 moles of Oxygen to form 5 moles of water, or 5×18=90g of water. Here is the required reaction:
H2(5mol.)+12O2(2.5mol.)→H2O(5mol.)
In reality, if 10g of hydrogen is burned with excess Oxygen, instead of water, Hydrogen Peroxide would be formed.
And stoichiometrically, with 10g of Hydrogen, that is 5 moles of Hydrogen, 5 moles of H2O2 would be formed. That is 5×34=170g of H2O2
Here is the required reaction:
H2(5mol.)+O2(5mol.)→H2O2(5mol.)
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