Question

Calculate the mass of urea co(nh2)2 present in 0.25 molal aqueous solution of urea

Answer 1



Secondary School

Chemistry

5 points

Calculate the mass of Nitrogen in 1000 kg of Urea CO (NH2)2

Ask for details 

Follow 

Report

 by Satvik22106.04.2018

Answers



Incredible29 

Ace

Heya user , 
Here is your answer !!

Molar mass of urea 
= 12 + 16 + 2 ( 14 + 2 )
= 28 + 2 × 16
= 28 + 32 
= 60 .

Molar mass of nitrogen = 14 .

Amount of nitrogen present by mass in 60 g of urea = 28 g .

So , mass of Nitrogen in 1000 kg of Urea CO(NH2)2 is :--

= ( 28 / 60 ) × 1000 kg 
= 466.67 kg ....... [ Ans ]

Hope it helps you !!

Answer 2

HEY....

HERE'S YOUR....

HIGH RATED GABRU---HARSH ♦️♦️♦️♦️♦️♦️♦️♦️♦️♦️

Given that

Mass of solution = 2.5 Kg

Molality = 0.25 m

Molar mass of urea (NH2CONH2) =14 + 2 × 1 + 12 + 16 + 14 + 2 × 1 = 60 g mol−1

Let mass of urea (NH2CONH2) = w gram

Number of moles of urea = w / 60 = 0.01667 mol

Mass of urea in Kg = w/1000 = 0.001w kg

Mass of solvent = total mass - mass of solute = 2.5 - 0.001 w kg

Use the above formula we get

Cross multiply and solve for the value of w we get

w = 37 g of urea

♦️♦️♦️♦️♦️♦️♦️♦️♦️♦️