Question

calculate the mass of urea (nh2conh2) required in making 2.5 kg of 0.25 molal aqueous solution.​

Answer 1

Let the mass of solution be 100 gm

Let the mass of solution be 100 gmMass of Benzene =30 gm

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gm

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene =

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 78

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 =

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 = 154

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 = 15470

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 = 15470

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 = 15470 =0.45 moles

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 = 15470 =0.45 molesMole fraction (Benzene) =

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 = 15470 =0.45 molesMole fraction (Benzene) = 0.385+0.45

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 = 15470 =0.45 molesMole fraction (Benzene) = 0.385+0.450.385

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 = 15470 =0.45 molesMole fraction (Benzene) = 0.385+0.450.385

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4 =70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 = 15470 =0.45 molesMole fraction (Benzene) = 0.385+0.450.385 =0.461

Answer 2

Let the mass of solution be 100 gm

Let the mass of solution be 100 gmMass of Benzene =30 gm

Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl

4 =70 gm

=70 gmMoles of Benzene =

=70 gmMoles of Benzene = 7830 =0.385

=70 gmMoles of Benzene = 7830 =0.385Moles of CCl

=70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 = 15470 =0.45 moles

=70 gmMoles of Benzene = 7830 =0.385Moles of CCl 4 = 15470 =0.45 molesMole fraction (Benzene) = 0.385+0.450.385 =0.461

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