Question

Calculate the mass of urea required to prepare 2.5kg 0.25 molal aqueous solution?​

Answer 1

37.5gram of urea is required to prepare 2.5kg 0.25 molal aqueous solution

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Answer 2

Solution :-

0.25 molal aqueous solution of urea means that 0.25 mole of urea are present in 1 kg of water  

0.25 molal aqueous solution of urea means that 0.25 mole of urea are present in 1 kg of water  Moles of urea = 0.25mole 

0.25 molal aqueous solution of urea means that 0.25 mole of urea are present in 1 kg of water  Moles of urea = 0.25mole Mass of solvent (water) = 1 kg = 1000 g 

0.25 molal aqueous solution of urea means that 0.25 mole of urea are present in 1 kg of water  Moles of urea = 0.25mole Mass of solvent (water) = 1 kg = 1000 g Molar mass of urea (NH2CONH2) = 60 g mol

0.25 molal aqueous solution of urea means that 0.25 mole of urea are present in 1 kg of water  Moles of urea = 0.25mole Mass of solvent (water) = 1 kg = 1000 g Molar mass of urea (NH2CONH2) = 60 g mol1. 0.25moleofurea=0.25mol×60gmol1=15g 

0.25 molal aqueous solution of urea means that 0.25 mole of urea are present in 1 kg of water  Moles of urea = 0.25mole Mass of solvent (water) = 1 kg = 1000 g Molar mass of urea (NH2CONH2) = 60 g mol1. 0.25moleofurea=0.25mol×60gmol1=15g Totalmassofsolution=1000+15g=1015g=1.015kg

0.25 molal aqueous solution of urea means that 0.25 mole of urea are present in 1 kg of water  Moles of urea = 0.25mole Mass of solvent (water) = 1 kg = 1000 g Molar mass of urea (NH2CONH2) = 60 g mol1. 0.25moleofurea=0.25mol×60gmol1=15g Totalmassofsolution=1000+15g=1015g=1.015kg Thus; 1.015 kg of solution contain urea = 15g×2.5kg of solution will require urea

0.25 molal aqueous solution of urea means that 0.25 mole of urea are present in 1 kg of water  Moles of urea = 0.25mole Mass of solvent (water) = 1 kg = 1000 g Molar mass of urea (NH2CONH2) = 60 g mol1. 0.25moleofurea=0.25mol×60gmol1=15g Totalmassofsolution=1000+15g=1015g=1.015kg Thus; 1.015 kg of solution contain urea = 15g×2.5kg of solution will require urea1.015kg15g×2.5kg = 37 g 

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