Question

Calculate the mass of volume of co2 gas at ntp by the complete composition of 570 g of octane c8 h18

Answer 1

Answer- The above question is from the chapter 'Some Basic Concepts of Chemistry'.

Given question: Calculate the mass of volume of CO₂ gas at NTP by the complete composition of 570 g of Octane C₈H₁₈.

(Atomic masses C = 12, H = 1 and O = 16)

Solution: Let's write the balanced chemical equation:

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

According to Stoichiometry, we see that,

2 moles of octane react with 25 moles of oxygen to produce 16 moles of carbon dioxide.

Using mass-mass relationship,

                                         2C₈H₁₈        16CO₂

                              (2 × 114)÷570    =   (16 × 44)÷x

                                                   x     =   507.65 g

∴ Mass of CO₂ produced = 507.65 g

Answer 2

Given Question :

Calculate the mass of volume of co2 gas at ntp by the complete composition of 570 g of octane C8H18.

Answer :

On balancing the equation, we get

7C8H18+25O2—>16CO2 + 18H2O

[mass of H =1g, C=12g, O=16g]

So, 7 moles of octane react with 25 moles of oxygen to produce 16 moles of carbon - dioxide.

Then, by using mass - mass relationship,

Mass of 2 moles of octane [2(C8H18)] = (12×8+1×18) =228 g.

And, mass of 16 moles of carbon- dioxide [16CO2]= 16×(12+16×2)=16 ×44 g

Then,accordingly we have

228/570 = 704 /x

x = 704×570/228

x = 507.65 gram.

Therefore, the mass of carbon-dioxide is 507.65 grams.