Calculate the mass of water formed by the complete combustion of 1.6g of methane
according to the equation CH4 + 2O2 CO2 + 2H2O
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No. of moles in 1.6 g of methane = 1.6/16 = 0.1 mole
0.1 mole of methane reacts with 0.2 moles of oxygen to form 0.1 mole of carbon dioxide and 0.2 moles of water
Now, mass of 0.2 moles of water = 0.2 x 18 = 3.6
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