calculate the mass of water having the same number of hydrogen atoms as are present in 32 g of methane ?
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So 8 moles of H will be present in (18 × 4=) 72g of H2O. Therefore, 72g of H2O will contain same number of H atoms as present in 32g of CH4.
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no. of atoms of H=8
Formula of water will be = H8O4
mass= 1*8 + 4*16 = 72
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