Question

calculate the mass of water molecule present in 3 mole of water. ​

Answer 1

Answer:

The mass of water molecules present in 3 moles of water is 5.40 grams.

Explanation:

The molar mass of a water molecule (H2O) is:

2(atomic mass of hydrogen) + 1(atomic mass of oxygen)

= 2(1.008 u) + 15.999 u

= 18.015 u

Therefore, the mass of one water molecule is 18.015 atomic mass units (u).

To find the mass of water molecules in 3 moles of water, we can use Avogadro's number, which is 6.022 × 10²³ molecules per mole. So, the total number of water molecules in 3 moles of water would be:

3 moles × 6.022 × 10²³ molecules per mole

= 1.8066 × 10²⁴ molecules

To find the mass, we can multiply the number of molecules by the mass of one molecule:

1.8066 × 10²⁴ molecules × 18.015 u/molecule

= 3.2536 × 10²⁵ u

Finally, we can convert this mass in atomic mass units to grams by using the conversion factor of 1 u = 1.66054 × 10⁻²⁴ g,

3.2536 × 10²⁵ u × (1.66054 × 10⁻²⁴ g/u)

= 5.40 g

Therefore, the mass of water molecules present in 3 moles of water is 5.40 grams.

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Answer 2

The mass of water molecule present in 3 mole of water is 53.97 grams.

To calculate

Mass of water molecule present in 3 mole of water,

Given

• The mass of a single water molecule is the molar mass (18.01 g/mol) divided by Avogadro’s number (6.022×10 23 molecules/mole).
• Mass of individual water molecule = 18.01 g/mol ÷ 6.022×10 23 molecules/mol =  $2.99* 10^{-23}$

Calculation

Then, to find the mass of water molecule present in 3 mole of water, we need to multiply the mass of individual water molecule by the number of molecules in 3 mole of water. That is,

mass of water molecule present in 3 mole of water = mass of individual water molecule x number of molecules in 3 mole of water

$= 2.99* 10^{-23} * 3 * 6.022 * 10^{23}$

= 53.97 grams

Therefore, the mass of water molecule present in 3 mole of water is 53.97 grams.

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