Calculate the mass per cent of different elements present in sodium sulphate (Na2SO4).
Answers
Answered by
20
Answer:.
ミ●﹏☉ミミ●﹏☉ミミ●﹏☉ミミ●﹏☉ミミ●﹏☉ミミ●﹏☉ミ
Atomic Mass of Sodium = 23g
Atomic Mass of Sulphur = 32g
Atomic Mass of Oxygen = 16g
From the molecular formula of sodium sulphate, it is understood that in 1 mole of sodium sulphate, 1 mole of sulphur, 4 moles of oxygen and 2 moles of sodium is present.
So Molecular Mass of Sodium Sulphate
= [23×2] + [32×1] + [16×4]
= 46 + 32 + 64
= 142g...
Percentage of Sodium in sodium sulphate = [46×100]/142
= [4600/142]
= 32.394%...
Percentage of Sulphur in sodium sulphate = [32×100]/142
= 3200/142
= 22.535%.
Percentage of Oxygen in sodium sulphate = [64×100]/142
= 6400/142
=45.070%......
Answered by
5
Answer:
Mass of element peresent in given compound =23+1(16×4)
=24+72
Explanation:
=96
%=0. 96
Similar questions