Question

calculate the mass per cent of different elements present in sodium sulphate Ha2SO4.​

Answer 1

Answer:

Molar mass of Na2SO4 = [(2 × 23.0) + (32.00) + 4 (16.00)] = 142 g

Mass percent of an element = (Mass of that element in compound/Molar mass of that compound) × 100

∴ Mass percent of sodium (Na): (46/142) × 100 = 32.39%

Mass percent of sulphur(S): (32/142) × 100 = 22.54%

Mass percent of oxygen:(O): (64/142) × 100 = 45.07%

Explanation:

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Answer 2

Answer:

Molar mass = atomic mass of Na(23)+ S(32.066)+O(16)

molar mass of (Na2So4) =(2×23.0) +(32.066)+(4×16.00)= 142.066

mass percent of sodium:

=46.0/142.066×100

=32.379

=32.4%

mass percent of sulphur:

=32.066/142.066×100

=22.57

=22.6%

mass percent of oxygen:

=64.0/142.066×100

=45.05%

Explanation:

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