Question

Calculate the mass percent of different elements present in sodium carbonate(Na2CO3)

Answer 1

Answer:

mass % of Na = 43.4%

mass % of C =  11.3%

mass % of O =  45.3 %

Explanation:

Gram Molecular Weight of Na₂CO₃ = (23 * 2) + (12 * 1) + (16 * 3) gm

                                                           = 106 gm

Total mass of Na in Na₂CO₃ = (23 * 2) = 46 gm

∴ mass % of Na = (46/106)  * 100 = 43.4%

Total mass of C in Na₂CO₃ = (12 * 1) = 12 gm

∴ mass % of C = (12/106)  * 100 =  11.3%

Total mass of O in Na₂CO₃ = (16 * 3) = 48 gm

∴ mass % of O = (48/106) * 100 = 45.3 %

Answer 2

Answer:

43.39% , 11.32% , 45.28%

Explanation:

mass of Na in N2CO3 =

$2 \times 23 \: \div \: (2 \times 23 \: + 12 + 3 \times 16) \times 100\%\: = \: 28.75\%$

similarly, mass of carbon =

$12 \div (2 \times 23 + \: 12 + 3 \times 16) \: \times 100\% = \: 11.3\%$

mass percentage of oxygen =

$(3 \times 16) \div \: ( 2 \times 23 + 12 + 3 \times 16) \times 100\%= \: \: 45.28\%$