Question

calculate the mass percent of sulphur in sulphuric acid​

Answer 1

Answer:

We need to find the molar mass of this acid, sulfuric acid: 2+32+4(16)=98 g/mol 2 + 32 + 4 ( 16 ) = 98 g / m o l .

Answer 2

Answer- The above question is from the chapter 'Some Basic Concepts of Chemistry'.

Mass Percent is a concentration term used to find the percentage of  mass of an element in a given compound.

Formula:

Mass % of an element = $\frac{Mass \: of \: element}{Molecular \: Mass \: of \: compound}$ × 100

Given question: Calculate the mass percent of sulphur in sulphuric acid​.

(Atomic masses of H = 1, S = 32 and O = 16)

Answer: Sulphuric Acid = H₂SO₄

Molecular Mass of H₂SO₄ = 2[H] + 1[S] + 4[O]

                                             = 2×1 + 1×32 + 4×16

                                             = 2 + 32 + 64

                                             = 98 g

Mass of Sulphur = 32 g

Mass % of S in H₂SO₄ = $\frac{Mass \: of \: element}{Molecular \: Mass \: of \: compound}$ × 100

                                     = $\frac{Mass \: of \: Sulphur}{Molecular \: Mass \: of \: Sulphuric \: Acid}$ × 100

                                     = (32 × 100) ÷ 98

                                    = 0.326 × 100

                                     = 32.6 %

∴ Mass percent of sulphur in sulphuric acid is 32.6 %.