Question

Calculate the mass percentage composition of copper in copper sulphate[Cu=64,S=32,O=16] ​

Answer 1

Explanation:

The molecular weight of water H

2

O=2(1)+16=18.

When 1 mole of CuSO

4

⋅5H

2

O is heated, 5 moles of water are lost.

The molecular weight of CuSO

4

⋅5H

2

O=64+32+4(16)+5(18)=250 g/mol

Mass of water lost =5(18)=90 g

Percentage loss of mass of CuSO

4

⋅5H

2

O=

250

90

×100=36 %.

Answer 2

Answer:

by dividing the formula weight of CuSO4 by the formula weight of CuSO4-5H2O and multiplying by 100 percent: 159.62 / 249.72 * 100 = 63.92 percent. This means that a 100-gram sample of copper sulphate pentahydrate will contain 63.92 grams of copper sulphate.