calculate the mass percentage of all elements in glucose
C6H12O6
Answers
Answered by
1
Explanation:
12×6+1×12+15×6= 72+12+90=174
Answered by
3
Answer:
6×c+12×h+6×o.
6×12u+12×1u+6×16u.
72u+12u+96u.
84u+96u.
180u.
so,mass of glucose=180u.
mass of carbon=72u.
so, mass%of carbon=72u/180u.×100.
=9/10×100.
=90%.
mass of hydrogen=12u.
so,mass%of hydrogen=12u/180u×100.
=6.6%.
mass of oxygen=96u.
so,mass%of oxygen=96u/180u×100.
=53.3%.
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