calculate the mass percentage of B4 in Na2B4O7.10H2O
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Answer:
Na= 23*2
B=10.8*4
O=16*7
H= 1
Na2B4O7.10H2O = 46+43.2+112+10*(2+16)
=381.2
B4= 43.2/381.2*100
=11.33
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