Question

calculate the mass percentage of benzene C6h6 is 22 grams of benzene is is dissolved in 122 grams of ccl4​

Answer 1

Mass of solution = Mass of benzene + Mass of carbon tetrachloride = 22 g + 122 g = 144 g Mass percentage of benzne = 15.28%. Mass percentage of CCl4 = 84.72%.

Answer 2

$\huge\tt\colorbox{lightblue}{Answer}$

In general percentage of X =

$\frac{mass \: of \: x \: }{mass \: of \: total \: mixture} \times 100$

Mass of total mixture = 22 + 122 = 144g

Mass percentage of benzene =

$( \frac{22}{144} ) \times 100 \\ \\ 0.1528 \times 100 \\ 15.28\%$

Additional information :

Mass percentage of $\ CCl_4$ =

$( \frac{122}{144} ) \times 100 \\ \\ 0.8472 \times 100 \\ 84.72\%$