Question

calculate the mass percentage of c h o in glucose​

Answer 1

Explanation:

1 Answer

Molecular mass of glucose (C6H12O6) = 6 × 12 + 1 × 12 + 6 × 16 = 72 + 12 + 96 = 180 g.

%of carbon(C) in glucose = 72 /180 × 100 = 40.

% of hydrogen (H) in glucose = 12/ 180 × 100 = 6.66.

% of oxygen(O) in glucose = 96/ 180 × 100 = 53.33.

Answer 2

Percentage composition of elements in compounds and carbon in C6H1206 = 72.06 × 100% = 40.0% by mass.....