Question

calculate the mass Percentage of c, h,o in glucose ( calculate it please anyone) please​

Answer 1

Explanation:

25%of carbon

50%of hydrogen

25%of oxygen

the formula is:c6h12o6

Answer 2

Molecular formula of Glucose = C₆H₁₂O₆

Molecular mass of Glucose = $\sf{6m_C + 12m_H + 6m_O}$

                                             = 6(12) + 12(1) + 6(16)

                                             = 180 g mol⁻¹

• Mass percentage of carbon -

$\longrightarrow\sf{ {\dfrac{Total \ mass \ of \ carbon}{Total \ mass \ of \ glucose}} \times 100 }$

$\longrightarrow\sf{ {\dfrac{6 \times 12}{180}} \times 100}$

$\longrightarrow\sf{ {\dfrac{72}{180}} \times 100 }$

$\longrightarrow$ 40 %

• Mass percentage of oxygen -

$\longrightarrow\sf{ {\dfrac{Total \ mass \ of \ oxygen}{Total \ mass \ of \ glucose}} \times 100 }$

$\longrightarrow\sf{ {\dfrac{6 \times 16}{180}} \times 100}$

$\longrightarrow\sf{ {\dfrac{96}{180}} \times 100 }$

$\longrightarrow$ 53.3 %

• Mass percentage of hydrogen -

$\longrightarrow\sf{ {\dfrac{Total \ mass \ of \ hydrogen}{Total \ mass \ of \ glucose}} \times 100 }$

$\longrightarrow\sf{ {\dfrac{12 \times 1}{180}} \times 100}$

$\longrightarrow\sf{ {\dfrac{12}{180}} \times 100 }$

$\longrightarrow$ 6.7 %