Calculate the mass percentage of each element present in water
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Answered by
33
Molar mass of water =H2O=1×2+16=18g/mol
Mass contributed by oxygen= 16g
Mass contributed by hydrogen =2g
Percentage of hydrogen =mass of hydrogen /molar mass of water=2/18=1/9 ×100= 0.11×100=11%
Percentage of oxygen =mass of oxygen/mass of water ×100= 16/18=0.88×100=88%
Mass contributed by oxygen= 16g
Mass contributed by hydrogen =2g
Percentage of hydrogen =mass of hydrogen /molar mass of water=2/18=1/9 ×100= 0.11×100=11%
Percentage of oxygen =mass of oxygen/mass of water ×100= 16/18=0.88×100=88%
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Answered by
13
hello buddy, here's ur answer
Mass percentage of each element present in water is given by
Lets the mass of any element be X
and molecular mass be XH20
and the mass percentage of an element M(X) is given by
M(X)% = M×100/X+ 18
since molecular weight of H20 IS 18
HENCE ,,,
MASS percentage of any element is given by
= M × 100/ X+18
Mass% of H = 2×1/18×100
Mass%H=11.1%
Mass of O= 16/18×100
Mass of O = 88.8%
HOPE IT HELPS U
Mass percentage of each element present in water is given by
Lets the mass of any element be X
and molecular mass be XH20
and the mass percentage of an element M(X) is given by
M(X)% = M×100/X+ 18
since molecular weight of H20 IS 18
HENCE ,,,
MASS percentage of any element is given by
= M × 100/ X+18
Mass% of H = 2×1/18×100
Mass%H=11.1%
Mass of O= 16/18×100
Mass of O = 88.8%
HOPE IT HELPS U
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