Calculate the mass percentage of H2SO4 required to make 1.8 molar H2SO4 solution (d = 1.8 g/cm³)
(1) 1.8
(2) 98
(3) 9.8
(4) 4.9
Answers
Answered by
1
Explanation:
1.8 molar H2SO4 solution means 1.8 moles of H2SO4 are present in 1 litre of solution
Now, the density of the solution is 1.8 g/cm^3
1 L =1000mL = 1000cm^3
Therefore, mass of solution = density × volume =1.8 × 1000 =1800 g
Mass of H2SO4 = moles × Molecular weight of H2SO4 = 1.8 × 98 = 176.4 g
Mass Percent of H2SO4= (Mass of H2S04/Mass of solution) × 100 = ( 176.4/1800)×100 = 176.4÷18 = 9.8 %
I hope it helps you!!!!
Similar questions