Calculate the mass percentage of oxygen present in the following compounds and state the law of chemical combination associated. Given, H = 1, O = 16. Water (H20) and Hydrogen peroxide (H202)
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Answered by
139
HEY !!!!! DEAR FRIEND HERE IS YOUR ANSWER
ACCORDING TO THE LAW OF MULTIPLE PROPORTION
1.H2O
Molecular mass = 2x 1+16 =18g
Mass % of O = (Mass of O in compound/ molecular mass) x 100
= (16/18)x 100 =88.9%
2.H2O2
Molecular mass = 2x 1+2x 16 =34g
Mass % of O = (2 x16/34) x 100 = 94.1%
HOPE IT HELPS ^_^
ACCORDING TO THE LAW OF MULTIPLE PROPORTION
1.H2O
Molecular mass = 2x 1+16 =18g
Mass % of O = (Mass of O in compound/ molecular mass) x 100
= (16/18)x 100 =88.9%
2.H2O2
Molecular mass = 2x 1+2x 16 =34g
Mass % of O = (2 x16/34) x 100 = 94.1%
HOPE IT HELPS ^_^
Answered by
17
Answer:
HEY !!!!! DEAR FRIEND HERE IS YOUR ANSWER
ACCORDING TO THE LAW OF MULTIPLE PROPORTION
1.H2O
Molecular mass = 2x 1+16 =18g
Mass % of O = (Mass of O in compound/ molecular mass) x 100
= (16/18)x 100 =88.9%
2.H2O2
Molecular mass = 2x 1+2x 16 =34g
Mass % of O = (2 x16/34) x 100 = 94.1%
HOPE IT HELPS ^_^
Explanation:
hope it help you !!!
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