Question

calculate the mass un grams of 3.01*10^20 milecules of glucose​

Answer 1

Answer:

The mass of 3.01 × 10²⁰ molecules of glucose in grams is  9 × 10⁻².

Explanation:

Given,

There are 3 × 10²⁰ molecules of glucose.

To find,

The mass of 3.01 × 10²⁰ molecules of glucose in grams.

Calculation,

The molecular formula of glucose is C₆H₁₂O₆.

We know that 1 mole of glucose contains 6.023 × 10²³ molecules. Then 3.01 × 10²⁰ molecules of glucose contain:

$\frac{3.01 \times 10^20}{6.02 \times 10^23} \ moles$

i.e. 3.01 × 10²⁰ molecules of glucose contain 5 × 10⁻⁴ moles.

Hence, the mass of 3.01 × 10²⁰ molecules of glucose(w) is:

w = no. of moles of glucose × G.M.W of glucose.

⇒ w = 5 × 10⁻⁴ moles × 180 g

⇒ w = 9 × 10⁻² grams.

Therefore, the mass of 3.01 × 10²⁰ molecules of glucose in grams is  9 × 10⁻².

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Answer 2

Answer:

3.01 × 10²⁰ molecules of glucose weighs 9 × 10⁻² grams

Explanation:

Given data: 3.01 × 10²⁰ molecules of glucose in the given sample.

To find: The mass in grams of 3.01 × 10² molecules of glucose.

Concept used: No.of molecules → No.of moles → Weight in grams using gram molecular weight of the molecule.

Solution:

The molecular formula of glucose is C₆H₁₂O₆

We know that one mole of any substance contains 6.023 × 10²³ molecules/atoms.

So using cross multiplication,

6.023 × 10²³ molecules = 1 mole of glucose

3.01 × 10²⁰ molecules = ?

= 3.01 × 10²⁰/6.023 × 10²³ moles of glucose.

= 5 × 10⁻⁴ moles of glucose.

So 3.01 × 10²⁰ molecules of glucose is equivalent to 5 × 10⁻⁴ moles of glucose.

Weight = no. of moles of glucose × G.M.W of glucose.

(G.M.V = Gram molecular weight)

Weight = 5 × 10⁻⁴ moles × 108 g/mole

= 9 × 10⁻² grams

So 3.01 × 10²⁰ molecules of glucose weighs 9 × 10⁻² grams.

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