Calculate the masses of cane sugar and water required to prepare 200 g of 15% mass by mass solution of cane sugar in water.
Answers
Answered by
142
mass percentage = mass of solute* 100/ mass of solution
15 %=mass of suger *100/ 200
so, mass of suger = 15*200/100
= 30 g
mass of water =mass of solution + mass of suger
= 200+ 30
=230 g
15 %=mass of suger *100/ 200
so, mass of suger = 15*200/100
= 30 g
mass of water =mass of solution + mass of suger
= 200+ 30
=230 g
Answered by
6
Concept
The solute is the substance that is dissolved in solution and the solvent is the substance in which a solute is dissolved or we can say that solvent has an efficiency to dissolve solvent.
Given
The mass of the sugar cane given is 200g
percentage mass given is 15%
Find
We need to find the mass by mass solution
Solution
mass percentage = mass of solute* 100/ mass of solution
15 %=mass of sugar *100/ 200
so, mass of sugar = 15*200/100 = 30g
mass of water =mass of solution + mass of sugar
= 200+ 30
=230 g
Hence the mass by mass solution in water is 230g
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