Question

calculate the maximm displacement of the sound wave in air whose frequency is 3.4khz and having the maximum pressure of 2.0pa

Answer 1

The maximum displacement of the sound wave  is 2.2 x 10^-7 m

• $A = \frac{Pmax}{2\pi fdV}$

• A is the maximum displacement
• Pmax is the maximum Pressure, Pmax = 2.0pa
• f is the frequency, f = 3.4khz
• d is the density of air, d = 1.22 Kg/m^3
• V is the velocity of sound in air, V= 346m/s

Therefore the maximum displacement is given by,

A = $\frac{2}{2\pi *3.4*10^{3} *1.22*346} = \frac{2*10^{-3} }{9017.677} = \frac{2*10^{-3} }{0.9017*10^{4} } = 2.2 * 10^{-7} m$