Chemistry, asked by ishikapatra2006, 10 hours ago

Calculate the maximum amount of NalO3 that can be produced by 12.8 g of Hl

6Hl + 2HNO3 → 3l2 + 2NO + 4H2O
3l2 + 6NaOH → NalO3 + 5Nal + 3H2O

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Answered by Anonymous

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