Question

Calculate the maximum and minimum wavelengths for the Lyman
series of hydrogen atom. (R = 1.097x107m-1)​

Answer 1

Answer:

1/max wavelength =1/R[1/(1)^2 - 1/(2)^2]

max wavelength =1/(1/R×3/4)=(4/3)×R

1/minimum wavelength =1/R[1/(1)^2 - 1/(infinity)^]

=1/R[1-0]

minimum wavelength=R