Question

Calculate the maximum horizontal distance travelled by a ball thrown with velocity of 20m/s without hittimg the ceailing of an auditorium of height 10m

Answer 1

here
H(max) = 10meter
$h(max) = \frac{ {u}^{2} {sin}^{2} \alpha }{2g}$
$10 = \frac{400 \times {sin}^{2} \alpha }{20}$
$\sin \alpha = \frac{1}{ \sqrt{2} }$
$\alpha = 45$

NOW,
$range = \frac{ {u}^{2} \sin(2 \alpha ) }{g}$
$range = \frac{400 \times 1}{20} = 20meters$
Here is your answer

GLAD YOU LIKE IT
PLEASE NOTE MY ANSWER AS BRAINLIEST