calculate the maximum normality of solution containing 13.4 G of solution of oxalate in 100 ml solution.answer this plzzz fast
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Answer:
Maximum normality = 134 eq/l .
Explanation:
The normality of a solution is the gram equivalent weight of a solute per liter of solution.
Normality = weight of solute / Volume in Litres
given that:
weight = 13.4g
volume = 100ml , which is equivalently 0.1litre
Therefore Normality = 13.4 / 0.1 = 134eq/l .
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