Question

calculate the maximum normality of solution containing 13.4 G of solution of oxalate in 100 ml solution.answer this plzzz fast

Answer 1

Answer:

Maximum normality = 134 eq/l .

Explanation:

The normality of a solution is the gram equivalent weight of a solute per liter of solution.

Normality =  weight of solute / Volume in Litres

given that:

weight = 13.4g

volume = 100ml , which is equivalently 0.1litre

Therefore Normality = 13.4 / 0.1 = 134eq/l .