Question

calculate the maximum stress at corner if 4600 kg wheel load is applied on cement concrete pavement of thickness 180mm

Answer 1

Answer:

The maximum stress at the corner is $42.59\frac{kg}{cm^2}$ .

Explanation:

What is stress?

Stress is defined as the force per unit area in materials that arises from external forces, uneven heating, or permanent deformation, and that enables accurate description and prediction of elastic, plastic, and fluid behavior.

Types of stress

The stress applied to the material can be of two types:

Tension in tension

The external force per unit area of ​​the material that causes the material to stretch is known as tensile stress.

Compressive stress

Compressive stress is the force that is responsible for deforming the material so that the volume of the material decreases.

What is a tribe?

Deformation is the amount of deformation experienced by the body in the direction of the applied force, divided by the initial dimensions of the body.

Voltage types

Body stress can be of two types depending on the application of stress as follows:

Tensile stress

The deformation or elongation of a solid body due to the application of tensile force or stress is called tensile strain. In other words, tensile strain occurs when a body increases in length as applied forces try to stretch it.

Compressive stress

Compressive strain is the deformation in a solid body due to the application of a compressive stress. In other words, compressive strain occurs when a body shortens in length when equal and opposite forces try to compress it.A

The maximum stress at corner is $42.59\frac{kg}{cm^2}$ .

Explanation:

Given that,

Mass of the wheel, m = 4600 kg

Thickness of the pavement, h = 180 mm = 18 cm

We need maximum stress at corner. To find the the stress the formula is as follows :

б=$\frac{3m}{h^2}$

б=$\frac{3*4600}{18^2}$

б=    $42.59\frac{kg}{cm^2}$

So, the maximum stress at corner is $42.59\frac{kg}{cm^2}$ .

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