Calculate The Mean Absolute Deviation For, 0.03, 0.05, 0.01?
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Answer:
x/0.01 + ( y + 0.03/0.05) = 2
⇒100x + (y + 3/5) = 2
⇒ 500x + 5y + 3 = 10
⇒ 500x + 5y = 7 ------(1)
Again, y/0.02 + (x + 0.03/0.04) = 2
⇒50y + x + 3/4= 2
⇒ 200y + 4x + 3 = 8
⇒4x + 200y = 5 --------(2)
equation (2) × 125 - equation (1),
125(4x + 200y ) - 500x + 5y = 125 × 5 - 7
⇒500x + 25000y - 500x + 5y = 625 - 7
⇒ 25005y = 618
⇒ y = 618/25005 = 0.02471 , put it in equation (1)
500x = 7 - 5y = 7 - 5 × 0.2471
⇒ x = 0.01375
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