Question

calculate the mean free path of Nitrogen molecules at 27°C when pressure is 1 atm​

Answer 1

Here, T=27oC=27+273=300K.

P=1atm =1.01×105N m−2, d=1.5Ao=1.5×10−10m,

kB=1.38×10−23J K−1,λ=?

From λ=2πd2pkBT=1.414×3.14(1.5×10−10)2×1.01×1051.38×10−23×300

=4.1×10−7m

Time interval between two successive collisions

t=speeddistance=vλ=6754.1×10−7=0.6×10−9s