Calculate the median from the following data:
x f
15 10
20 15
25 25
30 5
35 5
40 20
Answers
Answer:
RD Sharma Solutions for Class 10 Maths Chapter 7 Statistics Exercise 7.4
The median is the middle of a distribution. In this exercise, students will practice finding the median of a discrete and grouped frequency distribution. For quick access to solutions, the RD Sharma Solutions Class 10 is the best place. It has well-structured solutions in simple language to match the level of all the students. For detailed studies regarding this exercise, download RD Sharma Solutions for Class 10 Maths Chapter 7 Statistics Exercise 7.4 PDF provided below.
RD Sharma Solutions for Class 10 Maths Chapter 7 Statistics Exercise 7.4 Download PDF
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Access RD Sharma Solutions for Class 10 Maths Chapter 7 Statistics Exercise 7.4
1. Following are the lives in hours of 15 pieces of the components of aircraft engine. Find the median:
715, 724, 725, 710, 729, 745, 694, 699, 696, 712, 734, 728, 716, 705, 719.
Solution:
Arranging the given data in ascending order, we have
694, 696, 699, 705, 710, 712, 715, 716, 719, 721, 725, 728, 729, 734, 745
As the number of terms is an old number i.e., N = 15
We use the following procedure to find the median.
Median = (N + 1)/2 th term
= (15 + 1)/2 th term
= 8th term
So, the 8th term in the arranged order of the given data should be the median.
Therefore, 716 is the median of the data.
2. The following is the distribution of height of students of a certain class in a certain city:
Height (in cm): 160 – 162 163 – 165 166 – 168 169 – 171 172 – 174
No of students: 15 118 142 127 18Swipe left
Find the median height.
Solution:
Class interval (exclusive) Class interval (inclusive) Class interval frequency Cumulative frequency
160 – 162 159.5 – 162.5 15 15
163 – 165 162.5 – 165.5 118 133(F)
166 – 168 165.5 – 168.5 142(f) 275
169 – 171 168.5 – 171.5 127 402
172 – 174 171.5 – 174.5 18 420
N = 420 Swipe left
Here, we have N = 420,
So, N/2 = 420/ 2 = 210
The cumulative frequency just greater than N/2 is 275 then 165.5 – 168.5 is the median class such, that
L = 165.5, f = 142, F = 133 and h = (168.5 – 165.5) = 3
R D Sharma Solutions For Class 10 Maths Chapter 7 Statistics ex 7.4 - 1
= 165.5 + 1.63
= 167.13
3. Following is the distribution of I.Q of 100 students. Find the median I.Q.
I.Q: 55 – 64 65 – 74 75 – 84 85 – 94 95 – 104 105 – 114 115 – 124 125 – 134 135 – 144
No of students: 1 2 9 22 33 22 8 2 1Swipe left
Solution:
Class interval (exclusive) Class interval (inclusive) Class interval frequency Cumulative frequency
55 – 64 54.5 – 64-5 1 1
65 – 74 64.5 – 74.5 2 3
75 – 84 74.5 – 84.5 9 12
85 – 94 84.5 – 94.5 22 34(F)
95 – 104 94.5 – 104.5 33(f) 67
105 – 114 104.5 – 114.5 22 89
115 – 124 114.5 – 124.5 8 97
125 – 134 124.5 –
Answer:
yes upper answer is right