Physics, asked by RohitBarewar, 11 months ago

calculate the MI of a circular disc about an Axis passing through its centre and ler to its plan if mass of the disc is 2 kg and radius is equal to 50cm​

Answers

Answered by rishabh2004
5

Answer:

We have, moment of inertia of the disc about its diameter, Id =  

Let us suppose that x and y-axis are the two perpendicular diameters of the disc. Then,

Ix = Iy = Id =  

a.       If  is moment of inertia of the disc about an axis passing through its centre and normal to its plane, then according to the theorem of perpendicular axis,

            Iz = Ix + Iy =

 

b.       If ICD is the moment of inertia of the disc about an axis passing through a point on its edge and normal to its plane, then according to theorem of parallel axis,

            CD = z + Mh2 and h = R

 

           

 

   


RohitBarewar: numericals chahiye but
rishabh2004: yaar
RohitBarewar: bhejo na please
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