calculate the MI of a circular disc about an Axis passing through its centre and ler to its plan if mass of the disc is 2 kg and radius is equal to 50cm
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We have, moment of inertia of the disc about its diameter, Id =
Let us suppose that x and y-axis are the two perpendicular diameters of the disc. Then,
Ix = Iy = Id =
a. If is moment of inertia of the disc about an axis passing through its centre and normal to its plane, then according to the theorem of perpendicular axis,
Iz = Ix + Iy =
b. If ICD is the moment of inertia of the disc about an axis passing through a point on its edge and normal to its plane, then according to theorem of parallel axis,
CD = z + Mh2 and h = R
RohitBarewar:
numericals chahiye but
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