Question

Calculate the minimum pressure required to compress 250 L of air to 100 L at 1 bar keeping the temperature constant.

Answer 1

Hi

Here is your answer,

P₁ = 1 

P₂ = ?

V₁= 500 dm³

V₂= 200 dm³

Apply boyle's law  p₁V₁=p₂V₂ to calculate p₂ as temperature remains constant.

p₂ = p₁V₁/ V₂ = 1 bar × 500 dm³/ 200 dm³ = 2.5 bar

2.5 is the required answer ! 

Hope it helps you

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Answer 2

Given - V1 - 250L

V2 - 100L

P2 - 1 bar

Find - P1

Solution - The given question can be solved with the help of Boyle's Law.

It is an ideal gas law, which states that pressure and volume are inversely proportional to each other at constant temperature.

It can be mathematically expressed as -

P1V1 = P2V2

P1 and P2 is initial and final pressure. V1 and V2 is initial and final volume.

Keeping the values in equation-

P1*250 =1*100

P1 = 0.4 bar.

Answer - pressure required is - 0.4 bar