Chemistry, asked by saikireeti852, 10 months ago

Calculate the minimum pressure required to compress 500 ml of air at 1 atm pressure to 300ml at the same temperature

Answers

Answered by sreeh123flyback
18

Answer:

1.66 or 1.7 atm

Explanation:

we can use boyle law here

ie as preassure increses volume decrases

p inversley proportional to v at constant temeprature

p=k×1/v

pv=k

p2v2=p1v1

500×1=300×p

p=500/300=1.666 atm ie approx 1.7 atm

if

v=0.5L

v2=0.3L

p=1

p2=?

0.5×1=0.3×p

p =0.5/0.3=1.666 approx 1.7 atm

Answered by stalwartajk
1

Answer:

The minimum pressure required to compress 500 ml of air at 1 atm pressure to 300ml at the same temperature is 1.66 atm

Explanation:

Using Boyle's law,

Pressure \propto\frac{1}{volume}

p_{1} v_{1}  = p_{2} v_{2}

According to the question,

300 \times p_{1}  =500\times 1

p_{1} =\frac{500}{300}

=1.66 atm

∴The correct answer is 1.66 atm

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