Calculate the minimum wave length an electron can posses in a infinitely deep potential well of width 4nm
Answers
Answered by
5
Explanation:
Given Calculate the minimum energy an electron can possess in a infinitely deep potential well of width 4nm
- So we have a = 4 nm
- a = 4 x 10^-9 m
- The energy of an electron is given by
- E = n^2 h^2 / 8 ma^2 where n = 1,2,……
- So the minimum energy of the particle is got by taking n = 1
- So we have E = n^2 h^2 / 8 m a^2 where h is planck’s constant
- = 1^2 x (6.625 x 10^-34)^2 / 8 x 9.11 x 10^-31 x (4 x 10^-9)^2
- = 43.890625 x 10^-68 / 1166.08 x 10^-49
- = 0.037639 x 10^-19
- = 0.037639 x 10^-19 / 1.6 x 10^-19
- E = 0.02352 eV
Reference link will be
https://brainly.in/question/41287956
Similar questions