Question

Calculate the missing value of ""x"" in the following expression: (11/9)3× (9/11)6= (11/9)2x−1

Answer 1

Answer:

$= > ( \frac{11}{9} )3 \times ( \frac{9}{11} )6 = ( \frac{11}{9} )2x - 1 \\ = > 3 \times 6 = \frac{22x}{9} - 1 \\ = > 18 + 1 = \frac{22x}{9} \\ = > 19 = \frac{22x}{9} \\ = > x = \frac{19 \times 9}{22} \\ = > x = 8(approx.)$