Question

Calculate the missing value of “x” in the following expression:

(13/9)^3
× (9/13)
^6
= (13/9)^2x-1 Asap please​

Answer 1

⇒( 2x + 1 ) / ( 3x - 2 ) = 5/9

Do the cross multiplication,

We get,

⇒9 ( 2x + 1 ) = 5 ( 3x -2 )

⇒18x + 9 = 15x - 10

⇒18x - 15x = -10 - 9

⇒3x = -19

✯⇒x = - 19 / 3✯

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