Physics, asked by smyankotkar123, 1 day ago

Calculate the mobility of charge carriers in a doped silicon whose conductivity is 100 per ohm-m and the Hall Coefficient is 3.6X10^-4 m^3/coulomb. ( Ans in units of m^3/V-s

Answers

Answered by archanajhaa
5

Answer:

The mobility of charge carriers is 3.6×10⁻²m²V⁻¹s⁻¹.

Explanation:

The mobility of a semiconductor is given as,

\mu=\sigma R_H            (1)

Where,

μ=mobility of semiconductor

σ=conductivity of the semiconductor

RH=hall coefficient of the semiconductor

From the question we have;

σ=100/Ω-m

RH=3.6 ×10⁻⁴m³/C

By substituting the value of σ and RH in equation (1) we get;

\mu=100\times 3.6\times 10^-^4=3.6\times 10^-^2m^2V^-^1s^-^1

Hence, the mobility of charge carriers is 3.6×10⁻²m²V⁻¹s⁻¹.

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