Question

calculate the modarity of 9.8percentage W/w solution of H2sO4 if the dersity of the solution is 1.02 g ml -1 ? Molar mass of H₂SO4 → 98 g mol-1​

Answer 1

Answer :-

Molarity of the solution is 1.02 M .

Explanation :-

We have :-

→ Mass percentage of solute = 9.8 %

→ Density of the solution = 1.02 g/mL

→ Molar mass of H₂SO₄ = 98 g/mol

______________________________

Let us assume that the mass of solute [H₂SO₄] is 9.8 grams. So, mass of solution will be 100 grams .

Moles of solute :-

= Given Mass/Molar mass

= 9.8/98

= 0.1 mole

Volume of Solution :-

= Mass/Density

= 100/1.02

= 10000/102

= 98.04 mL

= 0.09804 L

Now, we have the required things from which we can calculate the molarity of the solution .

Molarity of the solution :-

= Moles of solute/Liters of solution

= 0.1/0.09804

= 10000/9804

= 1.02 M

Answer 2

Question:

• Calculate the molarity of 9.8% (w/w) solution of $\sf H_{2}SO_{4}$, if the density of the solution is 1.02 g/mL? Molar mass of $\sf H_{2}SO_{4}$ is 98 g/mol.

Answer:

• Molarity of the solution is 1.02 M.

Explanation:

Given that:

• Percentage of mass of solute = 9.8%
• Solution's density = 1.02 g/mL
• Molar mass of $\sf H_{2}SO_{4}$ = 98 g/mol

To Find:

• Molarity of the solution?

Solution:

• Let mass of $\sf H_{2}SO_{4}$ be 9.8 g
• So, mass of solution is 100 g

★ Finding number of moles ::

➻ No. of moles = Given mass/Molar mass

➻ No. of moles = 9.8/98

➻ No. of moles = 0.1 mole

★ Finding volume of solution ::

➻ Volume = Mass/Density

➻ Volume = 100/1.02

➻ Volume = 98.04 mL

• Volume in l :-

➻ Volume = 98.04/1000

➻ Volume = 0.09804 l

★ Finding molarity of solution ::

➻ Molarity = No. of moles/Volume of solution

➻ Molarity = 0.1/0.09804$\:$

➻ Molarity = 1.02 M

∴ Molarity of solution is 1.02 M.

Learn More:

Question:

• Calculate the molality of a solution of ethanol in water in which the mole fraction of ethanol is 0.04

Answer:

• brainly.in/question/41805095

★═══════════════════════★