Calculate the molal elevation constant of H2O, it being given that 0.1 molal aqueous solution of a substance boiled at 373.052K
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Answer:
5.2 kelvin kilogram mole
Explanation:
change in boiling point=given temperature - 373 k
=373.052-373
=0.52
change in temp.=molal elvation×molarity
molarity of sol=0.1m
0.52= k×0.1
k=0.52/0.1
k=5.2
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