Question

Calculate the molality and molarity of 93% h2so4(weight/volume). The density of the solution is 1.84g/ml.

Answer 1

:93 % H2SO4 w/v means 93 g of H2SO4 is present in 100cc of solution.

 

Since volume is 1000ml, amount of H2SO4 is 930 g/litre. Also density is given 1.84g/ml

M= density x volume = 1.84 x 1000 = 1840 g

 

wt of solvent = 1840 - 930 = 910 g

 

So, molality = 930/98 x 1000/910 = 10.43