Calculate the molality and mole fraction of solute in an aqueous solution of glucose containing 18g of glucose in 500g of water.
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Explanation:
Solving for molality
Molality = moles of solute / kilograms of solvent.
Molality = 18g / 180g per mole = 0.10 moles
Molality = 0.10 moles / 500g of water
Molality = 0.20 moles / 1 kg of water
Molality = 0.20 m
Solving for mole fraction
moles of glucose = 18g / 180 g/mole = 0.10 moles
moles of water = 500 g / 18 g per mole = 27.78 moles
mole fraction of solute = moles of solute / total moles in solution
mole fraction of solute = 0.10 mole / (0.10 mole + 27.78 moles)
mole fraction of solute = 0.10 mole / 27.88 moles
mole fraction of solute = 0.0036
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