Question

Calculate the molality and mole fraction of the solute in aqueous solution containing 3 gn of urea per 250 gm of water

Answer 1

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→→→→→→Solution←←←←←←

Molality=moles of solute(n)/weight of solvent(kg)

now,

no. of moles of solute=given mass/molar mass

=3/60=1/20→0.05mole

molality=0.05/0.2=0.5/2

Answer: 0.25

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→→→→→→Solution←←←←←←

moles of solvent=250/18=13.8

Mole fraction=no. of moles of solute/total mole

Answer: 0.05/13.8

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