Question

calculate the molality and mole function of the solute in aqueous solution containing 3.0 g of urea per 250g of water
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Answer 1

Answer:

Explanation:

Answer:

The molality and mole fraction of solute in aqueous solution containing 3g of urea in 250g of water is  0.2 mol/kg and 0.05 respectively.

Explanation:

Mass of urea in solution = 3 g

moles of urea =

Mass of water = 250 g

Moles of water =

Mole fraction of urea that is solute:

The molality and mole fraction of solute in aqueous solution containing 3g of urea in 250g of water is  0.2 mol/kg and 0.05 respectively.