calculate the molality and mole function of the solute in aqueous solution containing 3.0 g of urea per 250g of water
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Explanation:
Answer:
The molality and mole fraction of solute in aqueous solution containing 3g of urea in 250g of water is 0.2 mol/kg and 0.05 respectively.
Explanation:
Mass of urea in solution = 3 g
moles of urea =
Mass of water = 250 g
Moles of water =
Mole fraction of urea that is solute:
The molality and mole fraction of solute in aqueous solution containing 3g of urea in 250g of water is 0.2 mol/kg and 0.05 respectively.
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