calculate the molality of 0.2M nacl solution
Answers
Answered by
2
NaCl dissociates in a 1:1:1 ratio according to the equation:
NaCl --> Na+ + Cl-
So, based on this ratio if you have 0.2 molar NaCl you will get 0.2 molar Na+ and Cl-. The 1:1:1 ratio means that the molarity of each of the ions will be the same as the molarity of NaCl.
Contrast this to the situation for MgCl2. This dissociates in a 1:1:2 ratio:
MgCl2 --> Mg2+ + 2Cl-
In this case if you have 0.2 molar MgCl2, it will dissociate to give 0.2 molar Mg2+ but 0.4 molar Cl- because there are twice as many Cl- ions as MgCl2 particles.
NaCl --> Na+ + Cl-
So, based on this ratio if you have 0.2 molar NaCl you will get 0.2 molar Na+ and Cl-. The 1:1:1 ratio means that the molarity of each of the ions will be the same as the molarity of NaCl.
Contrast this to the situation for MgCl2. This dissociates in a 1:1:2 ratio:
MgCl2 --> Mg2+ + 2Cl-
In this case if you have 0.2 molar MgCl2, it will dissociate to give 0.2 molar Mg2+ but 0.4 molar Cl- because there are twice as many Cl- ions as MgCl2 particles.
Answered by
1
given mass / mass of solution in litre
0.2 M / 1 litre
sdk12:
density of Nacl is 1.25g/ml
Similar questions